3n^2-26=-7n

Solution for 3n^2-26=-7n equation:

3n^2-26=-7n

We move all terms to the left:

3n^2-26-(-7n)=0

We get rid of parentheses

3n^2+7n-26=0

a = 3; b = 7; c = -26;
Δ = b2-4ac
Δ = 72-4·3·(-26)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-19}{2*3}=\frac{-26}{6}
=-4+1/3
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+19}{2*3}=\frac{12}{6}
=2
$